Math, asked by khushiakbar07, 15 hours ago

find the area enclosed by each of the following figures

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Answers

Answered by COMMANDED
1

Answer:

orrect option is A)

Figure (i)

From the figure we can write,

Area of figure = Area of trapezium + Area of rectangle.

=

2

1

×( Sum of lengths of parallel sides )× altitude + Length × Breadth

=

2

1

(18+7)×8+18×18

=

2

1

×(25)×8+324

=100+324

=424

∴ Area of figure is 424cm

2

Figure (ii)

From the figure we can write,

Area of figure = Area of trapezium + Area of rectangle.

=

2

1

×( Sum of lengths of parallel sides )× altitude + Length × Breadth

=

2

1

(15+6)×8+15×20

=84+300

=384

∴ Area of figure is 384cm

2

Figure (iii)

Using Pythagoras theorem in the right angled triangle.

⇒ 5

2

=4

2

+x

2

⇒ x

2

=25−16

⇒ x

2

=9

∴ x=3cm

From the figure we can write,

Area of figure = Area of trapezium + Area of rectangle.

=

2

1

×( Sum of lengths of parallel sides )× altitude + Length × Breadth

=

2

1

(14+6)×3+4×6

=30+24

=54

∴ Area of figure is 54cm

2

.

Answered by SurajBrainlyStarz
1

Answer:

I hope it helps mark me brainliest

Step-by-step explanation:

=424

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