Question

Find the area enclosed by the given figure ABCDEF as per
dimensions given herewith.
E
6cm D
8 cm
20 cm
A 20cm-​

Answer 1

Answer:

Step-by-step explanation:

Given: A figure ABCDEF

AB = 20 cm

BC = 20 cm

ED = 6 cm

AF = 20 cm

AB || FC

FC = 20 cm

Let distance between FC and ED be h = 8 cm

FC || ED

Here,

From the figure we can see that ABCF forms a square and EFCD forms a trapezium.

Area of square = (side length) 2

Area of trapezium =  × (sum of parallel sides) × height

Therefore,

Area of the figure ABCDEF = Area of square (ABCF) + Area of trapezium (EFCD)

Here,

Area of square (ABCF) = (AB) 2 = (20)2 = 400 cm2

Area of trapezium (EFCD) =  × (FC + ED) × h =  × (6 + 20) × 8 = 104 cm 2

Area (ABCDEF) = Area of square (ABCF) + Area of trapezium (EFCD) = 400 + 104 = 504 cm2.

Area (Fig. ABCDEF) = 504 cm2.