find the area enclosed by the given figure. of 3cm 10cm 4cm 15cm
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Answer:
Now, Area of trapezium ABCD
=
2
1
× (Sum of parallel sides) × (height)
=
2
1
×(AB+CD)×(AF+FD)
=
2
1
×(5+3)×(5+4)
=
2
1
×8×9=36cm
2
Area of rectangle GAFE=Length×Breadth
=2×5=10cm
2
Hence,
Total area of the figure =36+10 cm
2
=46 cm
2
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