Math, asked by avneetkaur113239, 1 month ago

find the area enclosed by this figure in which each pair of consecutive sides are at right angles. ​

Attachments:

Answers

Answered by anshurani991
1

Answer:

The area is 76cm²

Step-by-step explanation:

First if all take the first part of figure of 4cm and 8cm

Their area is 8*4= 32cm²

Then take the second part of figure which is composed of 7cm and 4cm. Now, you can see that the length will be (7+4)cm

Therefore the area of this part is 11*4=44cm²

Bow add both the equations, you get

Total area of figure =44+32= 76cm²

At the end Please mark me brainliest


avneetkaur113239: Thanks
anshurani991: no problem
Answered by Anonymous
7

Given:

✰ Figure ( refer the attachment )

✰ Each pair of consecutive sides are at right angles i.e., 90°

To find:

✠ The area enclosed by this figure.

Solution:

As we know each pair of consecutive sides are at right angles i.e., 90°. Therefore, if we divide the figure into ABCD and CDEF, we will get two rectangles i.e., rectangle ABCD and rectangle CDEF.

First find out the area of rectangle ABCD.

Area of rectangle = length × breath

⇰Length of the rectangle ABCD = 4 cm

⇰Breath of the rectangle ABCD = 8 cm

  • Area of rectangle = l × b

  • Area of rectangle ABCD = ( 4 × 8 ) cm²

  • Area of rectangle ABCD = 32 cm²

Now, find out the area of rectangle CDEF.

Area of rectangle = length × breath

⇰Length of the rectangle CDEF = ( 4 + 7 ) cm

⇰Length of the rectangle CDEF = 11 cm

⇰Breath of the rectangle CDEF = 4 cm

  • Area of rectangle = l × b

  • Area of rectangle CDEF = ( 11 × 4 ) cm²

  • Area of rectangle CDEF = 44 cm²

Now, to find the total area enclosed by this figure, we will add both the area of rectangle ABCD and rectangle CDEF.

  • Area of figure = Area of rectangle ABCD + rectangle CDEF

  • Area of figure = ( 32 + 44 ) cm²

  • Area of figure = 76 cm²

Area enclosed by the figure = 76 cm²

▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Attachments:

BrainlyHero420: Perfect Answer !! :Clap: ❤️
Anonymous: Nice :p
Anonymous: w(°o°)w
Anonymous: Thank you everyone ^_^
Similar questions