Math, asked by Nabilrahman3244, 2 days ago

Find the area enclosed by
y=e^x, x=0, y=2, y=3

Answers

Answered by Awdeshsah
0

Answer:

Given curve is

y=e^x

<br> They x= In y <br> Area =

int_2^3xdy=int_2^3 Inycdotdy

<br>

[In ycdoty]_2^3-int_2^3 1/ycdotydy=[Inycdoty]_2^3-int_2^3 1/ycdotydy

<br> = (3 In 3 - 2 In 2) -

[y]_2^3

<br>

In 3^3/2^2 -(3-2)=In27/4-1

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