Question

FIND the area enclosed figure

Answer 1

Ans: Area of rectangle + 2 × Area of trapezium

=> (14 × 8) + 2 [1/2 × ( 8 + 16) × 11]
=> (112 + 264) cm^2
=> 376 cm^2

Hope it helps...!!

Answer 2

${\underline{\underline{\mathfrak{\large{Solution:}}}}}$

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Firstly,

finding the area of rectangle
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length : 14cm
breadth : 8 cm
area = l×b => 14×8 = 112 cm²

finding the area of trapezium
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height of one trapezium = (25-14)÷2 = 5.5cm
base (a) = 8 cm
base (b) = 16 cm
Area = $h \times \frac{a + b}{2}$
= 66 cm²

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area of enclosed figure = area of rectangle + area of two trapezium

= 112 + 132
= 244 cm²

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