find the area find the area of a triangle whose vertices are - 5 - 1 and 3 - 5 and 5, 2
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area of triangle ABC
X1=-5,Y1= -1,X2=3 ,Y2=-5, X3=5,Y3=2
1/2(X1(Y2-Y3)+X2(Y3-Y1)+X3(Y1-Y2))
= 1/2(-5(-5-2)+3(2-(-1))+5(-1-(-5)))
=1/2(-5(-7)+3(3)+5(4))
1/2 (35+9+20)
1/2(29+35)
=1/2(64)
=32square unit
hence area of triangle ABC is 32 square unit
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