Question

Find the area from a force of 46 N and a pressure of 2.3 pa?

Answer 1

Answer:

Given :-

• A force of 46 N and a pressure of 2.3 Pa.

To Find :-

• What is the area.

Formula Used :-

$\clubsuit$ Pressure Formula :

$\bigstar \: \: \sf\boxed{\bold{P =\: \dfrac{F}{A}}}\: \: \: \bigstar$

where,

• P = Pressure
• F = Force
• A = Area

Solution :-

Given :

• Force = 46 N
• Pressure = 2.3 Pa

According to the question by using the formula we get,

$\implies \sf\bold{P =\: \dfrac{F}{A}}$

$\implies \sf Pressure =\: \dfrac{Force}{Area}$

$\implies \sf 2.3 =\: \dfrac{46}{Area}$

By doing cross multiplication we get,

$\implies \sf 2.3 \times Area =\: 46$

$\implies \sf Area =\: \dfrac{46}{2.3}$

$\implies \sf\bold{\underline{Area =\: 20\: m^2}}$

$\therefore$ The area is 20 m² .

Answer 2

Given :-

A force of 46 N and a pressure of 2.3 Pa.

To Find :-

What is the area.

Formula Used :-

\clubsuit♣ Pressure Formula :

\begin{gathered}\bigstar \: \: \sf\boxed{\bold{P =\: \dfrac{F}{A}}}\: \: \: \bigstar\\\end{gathered}

★

P=

A

F

★

where,

P = Pressure

F = Force

A = Area

Solution :-

Given :

Force = 46 N

Pressure = 2.3 Pa

According to the question by using the formula we get,

\begin{gathered}\implies \sf\bold{P =\: \dfrac{F}{A}}\\\end{gathered}

⟹P=

A

F

\begin{gathered}\implies \sf Pressure =\: \dfrac{Force}{Area}\\\end{gathered}

⟹Pressure=

Area

Force

\begin{gathered}\implies \sf 2.3 =\: \dfrac{46}{Area}\\\end{gathered}

⟹2.3=

Area

46

By doing cross multiplication we get,

\begin{gathered}\implies \sf 2.3 \times Area =\: 46\\\end{gathered}

⟹2.3×Area=46

\begin{gathered}\implies \sf Area =\: \dfrac{46}{2.3}\\\end{gathered}

⟹Area=

2.3

46

\begin{gathered}\implies \sf\bold{\underline{Area =\: 20\: m^2}}\\\end{gathered}

⟹

Area=20m

2

\therefore∴ The area is 20 m²