Question

Find the area if trapezium whose parallel side are 26 cm and 14 cm and the distance between them is 12 cm

Answer 1

$We \: \: know \: \: that,$

$AREA \: \: OF \: \: TRAPEZIUM= 1/2(sum of parallel sides)×height$

$=1/2(26+14)×12$

$=1/2×40×12$

$=240cm²$

Answer 2

Step-by-step explanation:

Area of Trapezium= 1/2xh(a+b)

=1/2x12(26+14)

=6x40

=240cm