Question

Find the area ill mark brainiest right away if your correct

Answer 1

Answer:

• The area of the total figure is 45 cm sq.

Step-by-step explanation:

Let us name the image as in the attached image.

So,

CDEF is a rectangle

• DE = CF = 8 cm
• CD = EF = 5 cm

Area of the rectangle is

= length*breadth unit sq.

= 8 * 5

= 40 cm sq.

And,

ABG is a triangle on rectangle CDEF.

• CB = GF = 1 whole ½ cm = 1.5 cm
• AH is perpendicular to CF and AH = 2 cm. (height)

Now,

BG = 8 - [ (CB)+(GF) ]

BG = 8 - (1.5 + 1.5)

BG = 8 - 3

BG = 5 cm (base)

Thus,

Area of the triangle ABG is

= ½ * base * height

= ½ * 5 * 2

= 5 cm sq.

• The total area of the figure

= Area of rectangle+area of the triangle

= 40 + 5

= 45 cm²

Answer 2

Answer:

Question:-

Find the Area of the figure.

Answer:- 45cm^2

Explanation:-

DEFG is a rectangle so we have to find the area

So, the formula of area of rectangle to find the area of the figure is l × b

Here,

l = 8 cm

b = 5 cm

Area of rectangle = 8 × 5

Area of rectangle = 40

And,

the Area of triangle ABC:-

the formula to get area = 1/2 × b × h

we don't have the value of base

first we have to find value of base

the total length is 8

then,

total length - (DB + CG)

= 8-3

base length = 5cm

Thus the Area of triangle:-

Area of triangle = 1/2 × b × h

= 1/2 × 5 × 2 [ Here 2/2 will be cancelled]

= 5 cm .sq

Therefore the Area of complete figure:-

Area of rectangle DEFG + Area of triangle ABC

= 40 + 5

= 45 cm^2