find the area in square cm of a triangle whose base and altitude are as under base 18cm altitude 3.5 base 8dm altitude 15
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0
Answer:
We know that the area of a triangle =
2
1
×base×height
Area of the triangle =
2
1
×18×3.5=9×3.5=31.5sq.cm
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Answered by
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Step-by-step explanation:
Let's first divide this triangle into 2 parts
Base of first ∆ = 18cm
Altitude of 1st ∆ = 3.5 cm
Area of triangle = 1/2×18×3.5 = 9×3.5= 31.5cm^2
Base of 2nd ∆ = 8dm = 8×10cm = 80cm
Altitude of 2nd ∆ = 15 cm
Area = 1/2×base×altitude
1/2×80×15 = 40×15 = 600cm^2.
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