Math, asked by skamleshwari52gmail, 15 hours ago

find the area in square cm of a triangle whose base and altitude are as under base 18cm altitude 3.5 base 8dm altitude 15​

Answers

Answered by suhildewan35
0

Answer:

We know that the area of a triangle =

2

1

×base×height

Area of the triangle =

2

1

×18×3.5=9×3.5=31.5sq.cm

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Answered by shivansh457
0

Step-by-step explanation:

Let's first divide this triangle into 2 parts

Base of first ∆ = 18cm

Altitude of 1st ∆ = 3.5 cm

Area of triangle = 1/2×18×3.5 = 9×3.5= 31.5cm^2

Base of 2nd ∆ = 8dm = 8×10cm = 80cm

Altitude of 2nd ∆ = 15 cm

Area = 1/2×base×altitude

1/2×80×15 = 40×15 = 600cm^2.

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