Question

find the area,in square metres,of a rectangular whose length 180cm breadth 150cm​

Answer 1

Your Question :

Find the area , in square meters of a rectangle whose length is 180 cm and breadth is 150cm

Deep Explanation to your question :

Here we need to find the area whose value should be in square meters.

Here ,

Given:

Length = 180 cm

Breadth = 150cm.

To find :

Area in square metres.?

Solution :

Let's consider area of rectangle as x.

By putting formula : Area of rectangle = length × breadth.

Therefore , x = 180×150m²

Therefore , = 27000÷ 10000

= 27÷10

= 2.7m²

Therefore x = 2.7m²

Note:

( 180×150 = 27000)

(100×100=10000)

Hence , solved .

So here our answer came in square meters.

Answer 2

Given: Length and breadth of a rectangle i.e 180cm & 150cm.

Need to find: Area of the rectangle ?

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❍ Let's consider length and breadth of the rectangle as l & b & area as x.

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As we know that,

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$\begin{gathered}\star\:{\underline{\boxed{\frak{Area_{\:(rectangle)} = Length \times Breadth}}}}\\\\\\ \bf{\dag}\:{\underline{\frak{Putting\:given\:values\:inm\:formula,}}}\\\\\\ :\implies\sf 180 \times 150 \\\\\\ :\implies\sf 27000 \\\\\\ :\implies{\underline{\boxed{\frak{\purple{x = 27000 {cm}^{2} }}}}}\:\bigstar\\\\\end{gathered}$

As asked in metre square,

$\begin{gathered}\star\:{\underline{\boxed{\frak{1cm^2 = \frac{1}{10000}m^2}}}}\\\\\\ \implies \sf \frac{27000}{10000} \\\\\\ :\implies{\underline{\boxed{\frak{\purple{x = 2.7 {m}^{2} }}}}}\:\bigstar\\\\\end{gathered}$

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Therefore,

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Area of the rectangle , x = 2.7m².

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$\therefore\:{\underline{\sf{Hence,\:Area \: of \: the \: rectangle \: is \: \bf{2.7\:m^2}\: \sf{respectively}.}}}$

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$\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}$