Question

find the area ,in square root of the trapezium whose bases is 16dm and 10 dm and altitude is 90 cm​

Answer 1

Answer:

16 dm = 1.6 m

And, 10 dm = 1m

Altitude = 90 cm=0.9m

Area of trapezium = 12×(Sumofbases)×(Altitude)

=12(26)(0.9)

=280.8 dm