find the area level by cylindrical roller of diameter 60 cm and length 2.1 m in 150 revolution
Answers
Answered by
9
Formula 2 πrh
First convert h into meter 60/100=0.6
2*22*0.6*2.1/7=7.92
Revolution of cylindrical roll is 150/7.92=18.93
First convert h into meter 60/100=0.6
2*22*0.6*2.1/7=7.92
Revolution of cylindrical roll is 150/7.92=18.93
Similar questions