Find the area levelted by a cylinder roller of diameter 60cm and length 2.1m is 150 revolutions?
ShuklaDivy:
594 sqm
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d = 60cm = 0.6m
=> r = d/2 = 0.6/2 =0.3m
h = 2.1m
Area levelled in one revolution = 2πrh
Area levelled in 150 revolution = 150 x 2πrh
Put the values of π,r,h and you will get your answer
=> r = d/2 = 0.6/2 =0.3m
h = 2.1m
Area levelled in one revolution = 2πrh
Area levelled in 150 revolution = 150 x 2πrh
Put the values of π,r,h and you will get your answer
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