Math, asked by krishnapatel15164, 2 months ago

find the area.

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need help​

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Answered by zoyabagwan70
0

Answers:

Area of the quadrilateral = area of the triangle ABD + area of the triangle DBC.

From ΔDBC, BC 2 =DC 2 −BD 2

[Using Pythagoras theorem]

⟹BC 2 =13 2−12 2=25 , ⟹BC= 25=5 cm

Area of the ΔDBC= 21 ×b×h= 21 ×5×12=30 cm 2Area of the ΔABD= s(s−a)(s−b)(s−c)

Here, s= 210+12+8=15 cm ∴ Area of the ΔABD= 15(15−10)(15−12)(15−8)=15 7 cm 2

∴ area of the quadrilateral=15+15 7 =15(1+ 7) cm 2

Answered by JeyanthS
1

Answer:

since BC=10cm, BD=5 cm

In triangle ADB,

By Pythagoras theorem,

AB²= AD²+BD²

SO,

AD²=AB²-BD²

= 13²-5²

= 169-25

AD² =144

therefore AD=12CM

Area of triangle ABC=1/2×BASE×HEIGHT

=1/2×10×12

=5×12

=60cm²

area of triangle ABC=60cm²

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