Find the area od quadrilateral ABCD whose sides are 9cm,40cm,28cm and 15cm respectively, in consecutive order ,and angle between first two sides is 90 degree.
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AB= 9
BC= 40
CD= 28
DA= 15
join A and C to form a diagonal AC in quadrilateral ABCD
using pythagorean theorem,
AB ^(2) + BC ^(2) = AC ^(2)
9*9 + 40*40 = AC ^(2)
81 + 1600 = AC ^(2)
1681 = AC^(2)
[tex] \sqrt{1681} [/tex] = AC
41 = AC
now, using herons formula, u can find the area of triangle ABC an d triangle ADC.
in triangle ABC
=
=
=
=
= 5*3*2*3*2
= 5*36
= 180
in triangle ADC
=
=
=
=
=2*7*3*3*
= 14*9
= 126
area of ABC + area of ADC = area of ABCD
180 + 126 = 306
BC= 40
CD= 28
DA= 15
join A and C to form a diagonal AC in quadrilateral ABCD
using pythagorean theorem,
AB ^(2) + BC ^(2) = AC ^(2)
9*9 + 40*40 = AC ^(2)
81 + 1600 = AC ^(2)
1681 = AC^(2)
[tex] \sqrt{1681} [/tex] = AC
41 = AC
now, using herons formula, u can find the area of triangle ABC an d triangle ADC.
in triangle ABC
=
=
=
=
= 5*3*2*3*2
= 5*36
= 180
in triangle ADC
=
=
=
=
=2*7*3*3*
= 14*9
= 126
area of ABC + area of ADC = area of ABCD
180 + 126 = 306
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