find the area of 2m wide path around a rectangular park whose length is 15m and breadth is 10m.
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In rectangle ABCD,
Length ‘L’: AB = CD = 2 + 15 + 2 = 19m
Breadth ‘B’: AC = BD = 2 + 10 + 2 = 14m
In rectangle EFGH (rectangular park),
Length ‘l’: EF = GH = 15m
Breadth ‘b’: EH = GF = 10m
Area of path = Area of ABCD - Area of EFGH
=> Area of path = LB - lb
=> Area of path = (19 x 14) - (15 x 10)
=> Area of path = 266 - 150
=> Area of path = 116 cm²
Therefore, area of path is 116 cm².
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In rectangle ABCD,
Length ‘L’: AB = CD = 2 + 15 + 2 = 19m
Breadth ‘B’: AC = BD = 2 + 10 + 2 = 14m
In rectangle EFGH (rectangular park),
Length ‘l’: EF = GH = 15m
Breadth ‘b’: EH = GF = 10m
Area of path = Area of ABCD - Area of EFGH
=> Area of path = LB - lb
=> Area of path = (19 x 14) - (15 x 10)
=> Area of path = 266 - 150
=> Area of path = 116 cm²
Therefore, area of path is 116 cm².
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