Question

find the area of a a rhombus whose side is 5 cm and altitude is 4.8 cm . If one of it's diagonals is 8 cm find the length of the other diagonal

Answer 1

area= base × height
5cm × 4.8cm
24.0cm^2

length of other diagonal: 1/2×diagonal 1 ×diagonal2= areA
24cm^2=1/2×8cm×diagonal 2
24cm^2=4cm× diagonal 2
diagonal 2= 24cm^2/4cm
diagonal 2= 6 cm

Answer 2

Since,a rhombus is also a kind of a parallelogram.

Formula of area of rhombus =Base×Altitude

Putting values, we have

Area of rhombus =5×4.8=24

Since, Area of rhombus is 24 cm².

Also,formula for area of rhombus =$\frac{1}{2}×d_1d_2$

Given,Length of one diagonal =$d_1$=8

Let length of other diagonal =$d_2$

After substituting the values, we get

$24=\frac{1}{2}×8×d_2$

$24=4×d_2$

$4×d_2=24$

$d_2=\frac{24}{4}$

$d_2=6$

Hence, length of other diagonal is 6 cm.