Question

find the area of a ΔABC with AB=12cm,BC=5cm,Angle B=90°,Hence, Find the length of BD where BD perpendicular to AC​

Answer 1

Answer: 13 cm

Step-by-step explanation:

As per the question

ABC is a triangle , in which ∠ B = 90 °

AB = 12 cm , BC = 5 cm

BC is the base of the Δ ABC

AB is the perpendicular of Δ ABC

AC is the hypotenuse of Δ ABC

We have to find AC, using Pythagoras theorem

H ² = P ² + B ²

AC ² = 12 ² + 5 ²

AC ² = 144 + 25

AC ² = 169

AC = √ 169

AC = 13

So, the hypotenuse is 13 cm

Hypotenuse is the circumradius of triangle

Answer 2

Answer:

13

Step-by-step explanation:

By Pythagoras theorem, (hypotenuse)2 = (perpendicular)2 + (base)2

∴AC2 = BC2 + AB2

= AC2 = (5)2 + (12)2

= AC2 = 25 + 144

= AC2 = 169

= (13)2

→ AC = 13

may this answer will help you. thanks