Question

Find the area of a circle circumscribing a square of side 6 cm.


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Answer 1

area of circle=26.64sq cm.

Step-by-step explanation:

for first condition,

side of square=6 cm

so therefore,

area of square=side2

=6×6

=36 sq cm

then,

finding the diameter,

by using theorem of pythagorous,

( hypt)2= (side1)2 +(side2)2

= 6×6 +6×6

= 36+36

= 72

hypt =√72

=6√2

for second condition,

hypt means the diameter of the circle

area of circle=Πd

=3.14 × 6√2

=26.64 sq cm