Question

Find the area of a circle circumscribing a square of side 6cm.

Answer 1

Answer:

Step-by-step explanation:

Given that circle is circumscribing the square.

So, diameter of circle = side of square = 6 cm

So, radius of circle = 6/2 = 3 cm

Now, Area of circle = $\pi$r² = 3.14 × 3 × 3 = 28.26 cm².

Answer 2

Answer:

Step-by-step explanation:

First of all, square is inscribed in the circle, so the diameter of circle is equal to the daigonal of square...

So to find daigonal we can use Pythagoras theorem as square all angles are 90°...

Therefore, side = 6 cm

Let ABCD be square...BD is daigonal...

AB^2+AD^2=BD^2

6^2+6^2=BD^2

36+36=BD^2

72=BD^2

√72=BD

6√2=BD

Therefore, daigonal of circle is 6√2cm.

Radius =6√2/2

=3√2cm

Then by applying formula for area of circle we can find area of circle...

Area of circle = πr^2

=3.14* 3√2* 3√2

=3.14* 9* 2

=56.52 sq.cm

Therefore, the area of circle is 56.52sq.cm...

I hope this will help you