find the area of a circle circumscribing a square of side 6cm
With fig.
Answers
Answered by
1
Answer:
Step-by-step explanation:
It is given that the circle circumscribes a square.
•°•
Diameter of circle = Diagonal of square
Now,
Side of square = 6 cm
Diagonal of square = 2 √side = 2√6 cm
Now,
Diameter of circle = 2√6 cm
Radius of circle = ( 2√6 ) / 2 = √6 cm
Now,
Area of circle = πr²
= 22 / 7 × ( √6 )²
= ( 22 / 7 ) × 6
= 18.85 cm²
manya2026:
diagonal of a square =root2 ×side
even i wrote it
so diagonal should be 6 root2 and not 2 root6
then radius should be 3 root2 not root6
ok i will rectify
sis u had written 2 root side not root2 side
....
thank u
ans should be 56.5(approximately) I hope so..
Answered by
3
Heya
______________________________
GOOD MORNING
Radius of circle circumscribing a square = length of Diagonal of square / 2
=>
Let the length of diagonal of a square be a
USING PYTHAGORAS THEOREM
a² = 6² + 6²
=>
a =√(72)
=>
a = 6√2cm
Radius of circle = 6√2/2 = 3√2cm
Area of circle is =
3.14 × ( 3√2 )² = 56.52cm²
______________________________
GOOD MORNING
Radius of circle circumscribing a square = length of Diagonal of square / 2
=>
Let the length of diagonal of a square be a
USING PYTHAGORAS THEOREM
a² = 6² + 6²
=>
a =√(72)
=>
a = 6√2cm
Radius of circle = 6√2/2 = 3√2cm
Area of circle is =
3.14 × ( 3√2 )² = 56.52cm²
thanks for the ans , your solution right....
Good Morning.
:)
you are in which standered?
10..
ok.
Similar questions