Question

Find the area of a circle circumscribing an equilateral triangle of side 15 CM. (Take pi 3.14)​

Answer 1

Answer

Let the radius of the circle be r, this circle also circumscribing the equilateral

triangle of side a = 15 cm = so from the relation between radius and

side of triangle we get

$r = \frac{15}{ \sqrt{3} } cm$

$Area \: of \: \: the \: \: circle \: \pi( \frac{15}{ \sqrt{3} })^{2}$

$= 3.14 \times \frac{225}{3}$

=235.5cm²

hope it helps.

Answer 2

Answer:

Answer

Let the radius of the circle be r, this circle also circumscribing the equilateral

triangle of side a = 15 cm = so from the relation between radius and

side of triangle we get

r = \frac{15}{ \sqrt{3} } cmr=

3

15

cm

Area \: of \: \: the \: \: circle \: \pi( \frac{15}{ \sqrt{3} })^{2}Areaofthecircleπ(

3

15

)

2

= 3.14 \times \frac{225}{3}=3.14×

3

225

=235.5cm²

hope it helps.