Question

find the area of a circle whose center is origin and which passes through the point (-12,5)​

Answer 1

Answer :

530.66 sq. units

Solution :

• Note : Radius of circle : it is the distance between the centre and any point on its circumference .
• Area of the circle with radius R is equal to π•R² .

Here ,

It is given that , origin (0 , 0) is the centre of circle and passes through the point (-12 , 5) .

Thus ,

The radius of the circle will be the distance between the origin (0 , 0) and the point (-12 , 5) [ °•° (-12 , 5) lies on the circumference of the circle ]

Thus ,

=> R = √[(-12 - 0)² + (5 - 0)²]

=> R = √[(-12)² + 5²]

=> R = √[144 + 25]

=> R = √169

=> R = 13 units

Now ,

The area of the given circle will be given as ;

=> A = π•R²

=> A = 3.14 • 13²

=> A = 3.14 • 169

=> A = 530.66 sq. units

Hence ,

Required area is 530.66 sq. units .

Answer 2

$\huge{\boxed{\rm{\red{Question}}}}$

Find the area of a circle whose center is origin and which passes through the point (-12,5)

$\huge{\boxed{\rm{\red{Answer}}}}$

Here we have,

It is given that origin ( 0 , 0 ) is the centre of circle and passes through the point ( -12 , 5 ).

Thus,

The radius of circle will be the distance between the origin ( 0 , 0 ) and the point ( -12 , 5 )

( -12 , 5 ) point lie on the circumference of the circle.

Thus,

⚪R = √[(-12 - 0 )² + (5 - 0 )²]

⚪R = √[(-12)² + 5² ]

⚪R = √[144 + 25 ]

⚪R = √169

⚪R = 13 units.

Now,

The area of given circle will be as →

⚪A = 3.14 • 13²

⚪A = 3.14 • 169

⚪A = 530.66 unit²

Hence, the required area is 530.66 unit².

$\huge{\boxed{\rm{\red{More \: to \: know}}}}$

What is a circle ?

A circle is a shape consisting of all points in a plane that are a given distance from a given point, the centre

What is area of Circle ?

Area of a circle is the region occupied by the circle in a two-dimensional plane. Formula = πr²

What is circumference ?

In geometry, the circumference is the perimeter of a circle

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