Question

Find the area of a circle whose circumference is the same as the perimeter of a rectangle of length 8 m and breadth 3 M

Answer 1

As we know that :

Perimeter of Rectangle = 2(l+b)

According to the question :

Circumference of Circle =

P.Of.Rectangle = 2(8+3) = 2×11 = 22 m.

As we know that : Circumference of Circle = 2πr

Again according to the question :

$2 \times \frac{22}{7} \times r = 22 \\ \\ = > r = 3.5$

Area of Circle = πr²

$= > \frac{22}{7} \times 3.5 \times 3.5 \\ \\ = > 38.5$

So, the area of Circle will be 38.5 m²

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Answer 2

Answer:

area of the circle =38.465

Step-by-step explanation:

given

perimeter of given rectangle is equal to the

perimeter of given rectangle is equal to the perimeter (circumference) of the given circle

here given

rectangle dimensions are length (l)=8m and breadth (b)=3m

perimeter of rectangle = 2(l+b)

= 2(8+3)m

= 2(11)m

= 22 m

perimeter of the circle=2πr

from given condition, 2πr=22

2r=22/(22/7) where π=22/7 (or) 3.14

2r=7

r=(7/2)

r=3.5

then the

area of the circle is π(r^2)

area=(3.14)(3.5)(3.5)

area=38.465