Question

Find the area of a circle whose diameter in 35cm​

Answer 1

${ \bold \red { \underline{\large{Required \: Answer : - }}}} \:$

${ \bold \green { \underline{\large{Given : - }}}} \:$

A circle with diameter 35 cm .

${ \bold \blue { \underline{\large{To \: Find : - }}}} \:$

Area of the given circle .

$\large\boxed{\purple{\tt{ ⇝\:So\:let's \:do\:it\::-}}}$

$radius\: of \:circle \:= \:\dfrac{d}{2}$

$\therefore$ $radius\:of\:given\:circle\:=$ $\boxed {\dfrac{35}{2}}$

$\large\boxed{\orange{\sf{Area\:of\:circle\:=\:πr^2}}}$

$\large\tt\underline{\pink{Let's\:put\:values\::-}}$

:$\large\implies$ $π\:×\:r\:×\:r$

:$\large\implies$ $\dfrac{22}{7} \: × \: \dfrac{35}{2} \: × \: \dfrac{35}{2}$

:$\large\implies$ $\dfrac{\cancel{22}}{\cancel{7}} \: × \: \dfrac{\cancel{35}}{\cancel{2}} \: × \: \dfrac{35}{2}$

:$\large\implies$ $\dfrac{11\:×\:5\:×\:35}{2}$

:$\large\implies$ $\dfrac{1925}{2}$

:$\large\implies$ $\cancel{\dfrac{1925}{2}}$

:$\large\implies$ $962.5$

$\large\underline{\boxed{\red{\sf\:\therefore{Area\:of\:given\:circle\:=\:962.5\:cm^2}}}}$

${ \bold \green { \underline{\large{Some\:more\:formulas\:of\:circle : - }}}} \:$

★ $Area \:of \:circle\: = \:πr^2$ ( We used this one ).

★ $Diameter \:of \:circle \:=\: 2\: × \:r$

★ $Circumference\: of \: circle \: = \: 2πr$

Ans completed

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Answer 2

Question :-

Find the area of a circle whose diameter in 35cm ?

Given :-

• Diameter of circle = 35cm

To find :-

• Area of circle ?

___________

$radius \: of \: circle \: = \dfrac{diameter}{2}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀$r \: \: \: = \dfrac{35}{2}$

___________

Formula used :-

$\: \: \: \: area \: of \: circle \: = \: \pi {r}^{2}$

Solution :-

⠀$➠ \: \: \: \: \: \: \pi {r}^{2}$

⠀$➠ \: \: \: \: \: \: \dfrac{22}{7} \times \dfrac{35}{2} \times \dfrac{35}{2}$

⠀$➠ \: \: \: \: \: \: \dfrac{\cancel{22}}{\cancel7} \times \dfrac{\cancel{35}}{\cancel2} \times \dfrac{35}{2}$

⠀$➠ \: \: \: \: \: \: \dfrac{11 \times 5 \times 35}{2}$

⠀$➠ \: \: \: \: \: \: \dfrac{1925}{2}$

⠀$➠ \: \: \: \: \: 962.5 \: \: \: \: (in \: decimal \: form)$

_____________

$\mathcal{\underbrace{Lets\:explore\:more\::- }}$

1. Area A = $π{r}^{2}$

2. Circumference C = $2πr$

3. Diameter D = $2r$

4. Radius R = $\sqrt{ \dfrac{A}{π} }$

R $⟼$ Radius

C $⟼$ Circumference

D $⟼$ Diameter

A $⟼$ Area