Math, asked by nishi80npgmailcom, 4 months ago

Find the area of a equalaterel triangle with side 10 cm . please answer it quickly if u know ​

Answers

Answered by aryan073
32

Given :

The side of a equilateral triangle =10cm

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To Find :

• The area of a equilateral triangle =?

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Formulas :

\\ \sf{Area \: of \: a \: Equilateral \: triangle =\dfrac{\sqrt{3}}{4} (side) ^{2}}

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Solution :

• Side =10cm

 \\  \implies \sf \: area \: of \: a \: equilateral \: triangle =  \frac{ \sqrt{3} }{4}  {(side)}^{2}  \\  \\  \\  \implies \sf \: area \: of \: a \: equilateral \: triangle =  \frac{ \sqrt{3} }{4}  {(10)}^{2}  \\  \\  \\  \implies \sf \: area \: of \: a \: equilateral \: triangle =  \frac{ \sqrt{3} }{4}  \times 100 \\  \\  \\  \implies \boxed{ \sf{area \: of \: a \: equilateral \: triangle \: is \: 25 \sqrt{3}  {cm}^{2} }}

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Additional Formulas :

•Area of rectangle =\bf{L \times b}

•Area of triangle =\bf{\dfrac{1}{2}(b \times h) }

Answered by HA7SH
127

Step-by-step explanation:

______________________________

 \Large\bf{\underbrace{\underline{Question:-}}}

\leadsto  \sf{●\ Find\ the\ area\ of\ a\ equilateral\ triangle\ with\ side\ 10cm.}

 \Large\bf{\underbrace{\underline{To\ find:-}}}

\leadsto  \sf{●\ In\ this\ question\ we\ have\ to\ find\ the\ area\ of\ the\ equilateral\ triangle.}

 \Large\bf{\underbrace{\underline{Given:-}}}

\leadsto  \sf{●\ The\ side\ of\ a\ equilateral\ triangle\ =\ 10cm.}

 \large\bf{\underbrace{\underline{Formula\ to\ be\ used:-}}}

\leadsto  \sf{●\ Area\ of\ Equilateral\ triangle\ =\ \dfrac{√3}{4}\ (side)²}

 \Large\bf{\underbrace{\underline{Solution:-}}}

\leadsto  \sf{\qquad Area\ of\ equilateral\ triangle\ =\ \dfrac{√3}{4}\ (side)² \qquad}

\leadsto  \sf{\qquad Area\ of\ equilateral\ triangle\ =\ \dfrac{√3}{4}\ (10)² \qquad}

\leadsto  \sf{\qquad Area\ of\ equilateral\ triangle\ =\ \dfrac{√3}{4}\ ×\ 100 \qquad}

\leadsto  \sf{\qquad Area\ of\ equilateral\ triangle\ =\ 25\ \sqrt{3}cm². \qquad}

 \Large\bf{\underbrace{\underline{Hence,}}}

 \sf{●\ The\ area\ of\ equilateral\ triangle\ is\ 25\ \sqrt{3}cm²\ ●}

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