find the area of a field a b c d e f whose measurements in metre are given in figure 13.40 here acdf is a rectangle and angle E is equal to 90 degree
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Answer:
57,500
Step-by-step explanation:
Area of ABCDEF = Area (ABC) + Area (ACDF) + Area (DEF)
= (1/2×40×250)+(250×150)+(1/2×200×DE)
= 5000 + 37500 + (100×DE)
= 42500 + (100×DE)
For DE, in triangle DEF, using Pythagoras theorem:
250^2 = 200^2 + DE^2
62500 = 40000 + DE^2
DE^2 = 22500
So, DE = 150
Therefore, Area (ABCDEF) = 42500 + (100×150)
= 57,500
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ye answer hai dusro par mat kar barosa
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