Find the area of a field which is in the form of a right triangle with hypotenuse 13m and a side measuring 5m.
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Consider the △ABC,
whereAC=13cm;BC=12cm by phythagorus theorm
AC2=AB2+BC2⇒AB2=AC2+BC2∴AB=132−122=5cm
Area of △ABC=21×base×height=21×AB×BC=21×12×5=30cm2.
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