Question

find the area of a field whose length is 3x^2y+y^2and breadth is 4/5x^2y​

Answer 1

Answer:

Step-by-step explanation:

Length of field = 3x^(2)y+y^(2)

Breadth of field = 4/5x^(2)y

Hence, Area of field = l × b = 3x^(2)y+y^(2) × 4/5x^(2)y = 12/5x^(4)y^(2) + 4/5x^(2)y^(3)