Question

Find the area of a figure formed by square of side 8 cm and an isoceles triangle with base as one side of the square and perimeter as 18 cm​

Answer 1

Answer:

76

Step-by-step explanation:

Let x cm be one of the equal sides of an isosceles triangle. Given that the perimeter of the isosceles triangle = 18 cm Then, x + x + 8 =18 2x = (18 – 8) = 10 cm 2x = 10 x = 5 cm Area of the figure formed = Area of the square + Area of the isosceles triangle = (side of square)2 + ½ (base x √[(equal side)2 – ¼ x (base)2] = 82 + ½ (8) x √ [52 – ¼ x 82] = 64 + 4 x √ [25 – ¼ x 64] = 64 + 4 x √ (25 – 16) = 64 + 4 x √9 = 64 + 4 x 3 = 64 + 12 = 76 cm2Read more on Sarthaks.com - https://www.sarthaks.com/690518/find-the-area-figure-formed-by-square-of-side-cm-and-an-isosceles-triangle-with-base-one-side

Answer 2

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