find the area of a iscoceles triangle whose base is 16 cm and length of each of the equal sides is 10 cm
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Base = 16 cm.
Length of both equal sides = 10cm.
We will use Heron's formula to find the area,
Side 1, a = 16 cm.
Side 2, b = 10 cm.
Side 3, c = 10 cm
Therefore,
Half perimeter= s = 1/2×(16+10+10)
= 36/2
s = 18 cm.
Using Heron's formula,
Hence, the area of given triangle is 48 cm².
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Length of both equal sides = 10cm.
We will use Heron's formula to find the area,
Side 1, a = 16 cm.
Side 2, b = 10 cm.
Side 3, c = 10 cm
Therefore,
Half perimeter= s = 1/2×(16+10+10)
= 36/2
s = 18 cm.
Using Heron's formula,
Hence, the area of given triangle is 48 cm².
mark it as a brainliest answer
follow me also
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