Question

find the area of a isoceles triangle whose base is 16cm and one of its equal side is 10cm

Answer 1

Step 1: Calculate "s" (half of the triangles perimeter):

s =  a+b+c/ 2 implies 16+10+10/2 =  18

Step 2: Then calculate the Area:

heron's formula A = sqrt( s(s-a)(s-b)(s-c) ) = sqrt( 18(2)(8)(8) )= 6*8= 48sq.cm