find the area of a isosceles Right triangle with 12cm as its equal sides
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1
Answer:
we can find third side by pythagorous and then find solution by 1/2base ×b×h
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4
Answer:
Let AB = AC = 12
Therefore By Pythagoras Theorem ,
BC ^2 = AB ^2 + AC ^2
therefore BC^2 = 144 +144 = 288
BC = 12√2
Area of isosceles triangle = 1 /2 × b × h
= 6 × 12√2
= 72 √2
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