Question

find the area of a isosceles triangle which has 24 cm and equal sides 20 cm each​

Answer 1

1/2*base*height

1/2*20*24

240 ans

Answer 2

• Given

• Sides of an Isosceles triangle -
• First side = 24 cm
• Two equal sides = 20 cm

• To find

• Area of Isosceles triangle

• Solution

$\purple{\bigstar}$ $\boxed{\underline{\sf{\sf{\dfrac{1}{2} \times base \times height}}}}$

Substitute the given values,

⟶ 1/2 × 24 × 20

⟶ 240 cm²

• Area of Isosceles triangle = 240 cm²

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More about Triangles -

Isosceles triangle -

• In this triangle two sides and two angles are equal.
• The sum of three angles of the Isosceles triangle = 180°

Equilateral triangle -

• In this triangle all sides are equal to each other.
• Each angle of equilateral triangle = 60°

Scalene triangle -

• In this triangle all sides are unequal.
• All the three angles of scalene triangle are unequal.

Some related formulae -

• Area of equilateral triangle = √3/4 a²
• Area of isosceles triangle = ½ × b × h
• Area of scalene triangle -
• Heron's formula = $\sf{\sqrt{s(s - a)(s - b)(s - c)}}$
• Perimeter = Sum of all three sides