Question

Find the area of a isosceles triangle whose each side is 13cm and whose base is 24cm

Answer 1

S= a+b+c/2
S=13+13+24/2
S=38
$\sqrt{38 \times (38 - 13) \times (38 - 13) \times (38 - 24)}$
You can solve this.

Answer 2

hence , the area of isosceles triangle is 60 cm2