Question

find the area of a isosceles triangle whose equal sides are 5 cm each and base is 6 cm​

Answer 1

Step-by-step explanation:

Hope it helps you!!!! :)

Answer 2

Answer :-

• Area of triangle ABC = 12 cm²

Given :-

• Measure of Equal side of isosceles triangle (AB = AC) = 5 cm

• Base of isosceles triangle (BC)  = 6 cm

To Find :-

• Area of triangle ABC

Explanation :-

In order to find the area of isosceles triangle, we use Heron's Formulae to find the area.

$\implies \boxed { \bold { Heron's \; Formulae = \sqrt{s(s - a) (s - b) (s - c)} }}$

Where,

• s = Semi-perimeter of triangle
• a = First side of triangle
• b = Second side of triangle
• c = Third side of triangle

Finding semi- perimeter of triangle,

$\rm = \frac{Side \: 1 + Side \: 2 + Side \: 3}{2}$

$\rm = \frac{5 + 5 + 6}{2}$

$\rm = \frac{16}{2}$

$\boxed { \implies \rm Semi \; perimeter = 8 \: cm }$

Now, substituting the values

$\implies \rm \sqrt{8(8 - 5) (8 - 5) (8 - 6)}$

$\implies \rm \sqrt{8 \times 3 \times 3 \times 2}$

$\implies \rm \sqrt{24 \times 6}$

$\implies \rm \sqrt{144}$

$\boxed { \implies \rm \bold {12 \: cm^2 }}$

Hence, the area of the isosceles triangle is 12 cm².

@Agamsain