Question

find the area of a kite whose diagonals are 18 cm and 6.4 CM solution​

Answer 1

GIVEN: Diagonal 1 (D1) = 18 cm

Diagonal 2 (D2) = 6.4 cm

TO FIND: Area of Kite

SOLUTION:

$By \: using \: the \: formula \: of \: kite \: that \: is = > \frac{1}{2} \times \: d1 \times d2$

Putting the value of Diagonals, we get:

$= > \frac{1}{2} \times d1 \times d2$

$= > \frac{1}{2} \times 18 \times 6.4$

$= > \frac{115.2}{2} = 57.6$

Hence, Area of Kite is 57.4 cm²

Answer 2

Step-by-step explanation:

diagonals are 18cm & 6.4cm

we know a kite has a shape of rhombus.

area of rhombus = 1 × D1 × D2

2

→ 1 × 18cm × 6.4cm

2

→ 57.6cm