Question

Find the area of a major sector of a circle of diameter 42 cm and central angle is 60˚​

Answer 1

Answer:

$1155 \: cm {}^{2}$

Step-by-step explanation:

Area of major sector = 360° - theta/360° × πr^2

Diameter of the circle = 42cm

Then r = 42/2 => 21cm

theta = 60°

=> 360°-60°/360° × πr^2

=> 300°/360° × πr^2

=> 10/12 × πr^2

=> 5/6 × πr^2

=> 5/6× 22/7× 21×21

=> 5/6× 22×3×21

=>5/3× 11×3×21

=>5×11×3×7

=>55×21

=>

$1155 \: cm {}^{2}$

Therefore, area of the major sector is 1155cm^2

Answer 2

Answer:

Answer:

1155 \: cm {}^{2}

Step-by-step explanation:

Area of major sector=360°-theta/360°×πr^2

Diameter of the circle = 42cm

Then r = 42/2 => 21cm

theta = 60°

Step-by-step explanation:

=> 360°-60°/360° × πr^2

=> 300°/360° × πr^2

=> 10/12 × πr^2

=> 5/6 × πr^2

=> 5/6× 22/7× 21×21

=> 5/6× 22×3×21

=>5/3× 11×3×21

=>5×11×3×7

=>55×21