Find the area of a major sector of a circle of diameter 42 cm and central angle is 60˚
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Answered by
1
Answer:
Step-by-step explanation:
Area of major sector = 360° - theta/360° × πr^2
Diameter of the circle = 42cm
Then r = 42/2 => 21cm
theta = 60°
=> 360°-60°/360° × πr^2
=> 300°/360° × πr^2
=> 10/12 × πr^2
=> 5/6 × πr^2
=> 5/6× 22/7× 21×21
=> 5/6× 22×3×21
=>5/3× 11×3×21
=>5×11×3×7
=>55×21
=>
Therefore, area of the major sector is 1155cm^2
Answered by
0
Answer:
Answer:
1155 \: cm {}^{2}
Step-by-step explanation:
Area of major sector=360°-theta/360°×πr^2
Diameter of the circle = 42cm
Then r = 42/2 => 21cm
theta = 60°
Step-by-step explanation:
=> 360°-60°/360° × πr^2
=> 300°/360° × πr^2
=> 10/12 × πr^2
=> 5/6 × πr^2
=> 5/6× 22/7× 21×21
=> 5/6× 22×3×21
=>5/3× 11×3×21
=>5×11×3×7
=>55×21
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