find the area of a parallelogram ABCD in which AB=28 cm,BC=26 cm and diagol AC=30 cm
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By Heron's formula ,we find s=28+26+30/2=42
Area of the triangle=square root of 42×12×16×14=336 cm^2
Area of the triangle=square root of 42×12×16×14=336 cm^2
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diagonal of a parallelogram divides it into two congruent triangles here AC draw a figure and then find the area of ∆abc and multiply it by 2. and coils you get the answer
please mark as brainlest answer
please mark as brainlest answer
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