Question

Find the area of a parallelogram ABCD in which AB=28cm , BC=26cm and AC=30cm . AC is a digonal.​

Answer 1

Answer:

Step-by-step explanation:

we know that diagonal of parallelogram bisect it into two equal parts

by heron's formula

S=(28+26+30)/2= 42

area∆=√42(42-28)(42-26)(42-30)

√42×14×16×12=14×3×2×4=336

area of parallelogram=2(area∆)=2(336)=672

Answer 2

we know that diagonal of parallelogram bisect it into two equal parts

by heron's formula

S=(28+26+30)/2= 42

area∆=√42(42-28)(42-26)(42-30)

√42×14×16×12=14×3×2×4=336

area of parallelogram=2(area∆)=2(336)=672

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