Find the area of a parallelogram ABCD whose base
BC is 27 cm and altitude AE is 8 cm. If the length
of the altitude AF to the base CD is 12 cm. Find
CD.
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Solution:
Given DL ⊥ AB and DM ⊥ BC
Taking BC as the base, BC = 12 cm and altitude DM = 9.3 cm
We know that area of parallelogram ABCD = Base x Altitude
= (12 cm x 9.3 cm)
= 111.6 c m2 ….. Equation (i)
Now, by taking AB as the base,
We have, Area of the parallelogram ABCD = Base x Altitude
= (18 cm x DL) ….. Equation (ii)
From (i) and (ii), we have
18 cm x DL = 111.6 c m2
DL = 111.6/18
= 6.2 cm
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