Math, asked by parthamoshi, 21 days ago

Find the area of a parallelogram ABCD whose base
BC is 27 cm and altitude AE is 8 cm. If the length
of the altitude AF to the base CD is 12 cm. Find
CD.​

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Answers

Answered by ahikleshjha834797688
0

Answer:

Solution:

Given DL ⊥ AB and DM ⊥ BC

Taking BC as the base, BC = 12 cm and altitude DM = 9.3 cm

We know that area of parallelogram ABCD = Base x Altitude

= (12 cm x 9.3 cm)

= 111.6 c m2 ….. Equation (i)

Now, by taking AB as the base,

We have, Area of the parallelogram ABCD = Base x Altitude

= (18 cm x DL) ….. Equation (ii)

From (i) and (ii), we have

18 cm x DL = 111.6 c m2

DL = 111.6/18

= 6.2 cm

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