Question

find the area of a parallelogram PQRS if PR= 24 cm and QU=ST=6cm

Answer 1

area of triangle PSR=1/2×b×h
=1/2×24×6=72^2
area of triangle RQP=1/2×b×h
=1/2×24×6=72cm^2
area of parallelogram=72+72=144cm^2
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Answer 2

Area of parallelogram PQRS =area of triangle PRS +area of triangle PQR.
area of triangle PRS =1/2 *b *h
=1/2 *24 *6
=12*6
=72cmsq.
area triangle PQR =1/2 *B * H
=1/2*24*6 =72cmsq.
therefore, Area of parallelogram =72+72=142cmsq .
OR
area of parallelogram =2*area of triangle PQR.
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