Question

find the area of a parallelogram PQRS if PR = 24 cm and QU = ST = 6 cm​

Answer 1

Solution :-

$area \: of \: paralellogram \ = area \: (</strong><strong>PRS</strong><strong>) + area \: (</strong><strong>PQR</strong><strong>)$

$= > \frac{1}{2} (</strong><strong>PR</strong><strong>)(</strong><strong>ST</strong><strong>) + \frac{1}{2} (</strong><strong>PR</strong><strong>)(</strong><strong>UQ</strong><strong>) \\ = > \frac{1}{2} (</strong><strong>PR</strong><strong>)(</strong><strong>ST</strong><strong> + </strong><strong>UQ</strong><strong>) \\ = > \frac{1}{2} \times 24(12) = {144}cm^{2}$