find the area of a parallelogram PQRS if PR=24 cm and QU=ST=6cm
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cutting through PQ we get two triangles.
ΔSPR and ΔQPR
hence are of parallelogram= area of ΔSPR+ area of ΔQPR
Area of triangle=1/2(base) x (height)
area of ΔSPR=1/2(24)x(6)
=72 cm²
Area of ΔQPR=1/2(24)x(6)
=72 cm²
Total are of paralelogram=72+72=144 cm²
ΔSPR and ΔQPR
hence are of parallelogram= area of ΔSPR+ area of ΔQPR
Area of triangle=1/2(base) x (height)
area of ΔSPR=1/2(24)x(6)
=72 cm²
Area of ΔQPR=1/2(24)x(6)
=72 cm²
Total are of paralelogram=72+72=144 cm²
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