Question

find the area of a path 2 metres wide laid inside along the boundary of a rectangular Park of dimension 100 m × 60 M find the cost of gravelling it at the rate of rupees 30 per square metre​

Answer 1

Answer:

hey mate here your answer

Step-by-step explanation:

Length of inner field=100-4=96m

•Breadth of inner field=60-4=56m

•Area of outer field=100×60=6000m^2

•Area of inner field=96×56=5376m^2

•Now, Area of the boundary=6000-5376=624m^2

•So, the cost of gravelling=624×30=Rs18720.

Hope! it helped you!

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Answer 2

Answer:

★ Area of Path = 624 m² ★

★ Cost of gravelling path = Rs 18,720★

Step-by-step explanation:

Given:

• Length and Breadth of rectangular park is 100m and 60m respectively.
• Width of Park is 2 metres
• Cost of gravelling is Rs 30/m²

To Find:

• Cost of gravelling whole path

Solution: Let ABCD be a rectangular park .

★ Area of ABCD = Length x Breadth ★

$\small\implies{\sf }$ Area of ABCD = AB X BC

$\small\implies{\sf }$ Area of ABCD = 100 x 60

$\small\implies{\sf }$ Area of ABCD = 6000m²

★ In rectangle EFGH ★

• Length of EF = AB–(2+2)
• Breadth of FG = BC–(2+2)

∴ Area of EFGH = EF x FG

$\small\implies{\sf }$ Area of EFGH = 96 x 56

$\small\implies{\sf }$ Area of EFGH = 5376m²

Now we have to find the area of path:

• Area of Path = Area (ABCD – EFGH)

$\small\implies{\sf }$ Area of Path = ( 6000–5376)m²

$\small\implies{\sf }$ Area of Path = 624m²

Hence, Area of Path is 624m²

† Cost of gravelling 1 m² = Rs 30 †

∴ Cost of gravelling 624m² = 624 x 30

→ Rs 18,720

Hence, Cost of gravelling is Rs 18,720