Math, asked by billugautam89, 10 months ago

Find the area of a pentagon ABCDE in which AB =BC =CD=EA
and ED = 5 cm. Also, AD = BD=6 cm​

Answers

Answered by mohankumarlal146
2

Step-by-step explanation:

sabhi ka are nikange for ye sawal karenge

Attachments:
Answered by lublana
3

Area of pentagon=37.6cm^2

Step-by-step explanation:

AB=BC=CD=EA=ED=5cm

AD=BD=6cm

Heron's formula:

Area of triangle=\sqrt{s(s-a)(s-b)(s-c)}

Where s=Half perimeter

Half perimeter of triangle ADE=\frac{5+5+6}{2}=8

Half perimeter of triangle ABD=s=\frac{5+6+6}{2}=8.5

Half perimeter of triangle BCD=\frac{5+5+6}{2}=8cm

Area of triangle ADE=\sqrt{8(8-5)(8-5)(8-6)}=12cm^2

Area of triangle ADE=Area of triangle BCD=12 square cm

Area of triangle ABD=\sqrt{8.5(8.5-5)(8.5-6)(8.5-6)}=13.6cm^2

Area of pentagon=Ar(ADE)+ar(ABD)+ar(BCD)=12+12+13.6=37.6cm^2

Area of pentagon=37.6cm^2

#Learns more:

https://brainly.in/question/3915116:Answered by RohitkumarGupta

Attachments:
Similar questions