Question

Find the area of a pentagon ABCDE in which AB =BC =CD=EA
and ED = 5 cm. Also, AD = BD=6 cm​

Answer 1

Step-by-step explanation:

sabhi ka are nikange for ye sawal karenge

Answer 2

Area of pentagon=$37.6cm^2$

Step-by-step explanation:

AB=BC=CD=EA=ED=5cm

AD=BD=6cm

Heron's formula:

Area of triangle=$\sqrt{s(s-a)(s-b)(s-c)}$

Where s=Half perimeter

Half perimeter of triangle ADE=$\frac{5+5+6}{2}=8$

Half perimeter of triangle ABD=$s=\frac{5+6+6}{2}=8.5$

Half perimeter of triangle BCD=$\frac{5+5+6}{2}=8cm$

Area of triangle ADE=$\sqrt{8(8-5)(8-5)(8-6)}=12cm^2$

Area of triangle ADE=Area of triangle BCD=12 square cm

Area of triangle ABD=$\sqrt{8.5(8.5-5)(8.5-6)(8.5-6)}=13.6cm^2$

Area of pentagon=Ar(ADE)+ar(ABD)+ar(BCD)=12+12+13.6=$37.6cm^2$

Area of pentagon=$37.6cm^2$

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