Math, asked by rahulsingh447rhs, 10 months ago

Find the area of a plot which is in the shape of a quadrilateral, one of whose diagonals is 20 m and lengths of the perpendiculars from the opposite corners on it are of lengths 12 m and 18 m respectively.​

Answers

Answered by wwwadityakamar99
3

Answer:

300m²

Step-by-step explanation:

Area = (½ × 20 × 12) + (½ × 20 × 18 )

area = (10 × 12) + (10 × 18 )

area = 120 + 180

area = 300 m²

Answered by alfiya786786
5

Answer:

300m2

Step-by-step explanation:

Area of a Quardilateral=1/2×d (h1+h2)

So,diagonal=20m

height 1=12

height 2=18

According to the problem

1/2×20m(12m+18m)

=10m (30m)

=300m2

Similar questions