Question

Find the area of a quadrant of a circle whose circumference is 22 cm.​

Answer 1

Answer:

9.625 cm square

Step-by-step explanation:

we know that area of sector equals to theta/360 * pi *r^2

and circumference = 2pi *r

so, 22 = 2 * 22/7 * r

= r=3.5

now that the r is known and quadrant is always of 90deg. so we put the values in the sector formula and get above ans.

Answer 2

Circumference of circle=2πr

22=2×22/7×r

(22×7)/(2×22)=r

7/2=r

Area of quadrant = [90°×360°]× 22/7×7/2×7/2

=1/4×77/2

=77/8cm sq.

$hope \: this \: helps \: you$